What is (16a^4-40a^2+24a)/(12a^3) ?

The solution to (16a^4-40a^2+24a)/(12a^3) is (2(a-1)(2a^2+2a-3))/(3a^2)

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simplify (16a^4-40a^2+24a)/(12a^3)

simplify

\frac{16 a ^{4} - 40 a ^{2} + 24 a}{12 a ^{3}}

\frac{2 ( a - 1 ) ( 2 a ^{2} + 2 a - 3 )}{3 a ^{2}}

Solution steps

\frac{16 a ^{4} - 40 a ^{2} + 24 a}{12 a ^{3}}

Factor

16 a^{4} - 40 a^{2} + 24 a : 8 a (2 a^{3} - 5 a + 3)

= \frac{8 a ( 2 a ^{3} - 5 a + 3 )}{12 a ^{3}}

Factor

2 a^{3} - 5 a + 3 : (a - 1) (2 a^{2} + 2 a - 3)

= \frac{8 a ( a - 1 ) ( 2 a ^{2} + 2 a - 3 )}{12 a ^{3}}

Factor the number:

8 = 4 \cdot 2

= \frac{4 \cdot 2 a ( a - 1 ) ( 2 a ^{2} + 2 a - 3 )}{12 a ^{3}}

Factor the number:

12 = 4 \cdot 3

= \frac{4 \cdot 2 a ( a - 1 ) ( 2 a ^{2} + 2 a - 3 )}{4 \cdot 3 a ^{3}}

Cancel the common factor:

4

= \frac{2 a ( a - 1 ) ( 2 a ^{2} + 2 a - 3 )}{3 a ^{3}}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

a^{3} = a a^{2}

= \frac{2 a ( a - 1 ) ( 2 a ^{2} + 2 a - 3 )}{3 a a ^{2}}

Cancel the common factor:

a

= \frac{2 ( a - 1 ) ( 2 a ^{2} + 2 a - 3 )}{3 a ^{2}}

328 = 8 (5 - 6 x)

3 \cdot 4

x - 2.41 = 3.42

- 3 - 6 (4 x + 6) \geq - 111

\frac{3 ^{2}}{4}

What is (16a^4-40a^2+24a)/(12a^3) ?
The solution to (16a^4-40a^2+24a)/(12a^3) is (2(a-1)(2a^2+2a-3))/(3a^2)