What is 3.2E-17*(-1.6)*10^{-19} ?

The solution to 3.2E-17*(-1.6)*10^{-19} is -1/(5^{19)*1.024E22}

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simplify 3.2E-17(-1.6)10^{-19}

simplify

3.2 E - 17 \cdot (- 1.6) \cdot 1 0^{- 19}

- \frac{1}{5 ^{19} \cdot 1.024 E 22}

Decimal Notation

0

Solution steps

3.2 E - 17 (- 1.6) \cdot 1 0^{- 19}

Multiply the numbers:

3.2 E - 17 (- 1.6) = - 5.12 E - 17

= - 5.12 E - 17 \cdot 1 0^{- 19}

= - 1 0^{- 19} \cdot 5.12 E - 17

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 19} = \frac{1}{1 0 ^{19}}

= - \frac{1}{1 0 ^{19}} \cdot 5.12 E - 17

- \frac{1}{1 0 ^{19}} \cdot 5.12 E - 17 = - \frac{5.12 E - 17}{1 0 ^{19}}

= - \frac{5.12 E - 17}{1 0 ^{19}}

\frac{5.12 E - 17}{1 0 ^{19}} = \frac{512}{1.0 E 19 \cdot 1 0 ^{19}}

= - \frac{512}{1.0 E 19 \cdot 1 0 ^{19}}

Factor the number:

512 = 2^{9}

= - \frac{2 ^{9}}{1.0 E 19 \cdot 1 0 ^{19}}

Factor

1 0^{19} : 2^{19} \cdot 5^{19}

= - \frac{2 ^{9}}{1.0 E 19 \cdot 2 ^{19} \cdot 5 ^{19}}

\frac{2 ^{9}}{2 ^{19}} = \frac{1}{2 ^{10}}

= - \frac{1}{1.0 E 19 \cdot 2 ^{10} \cdot 5 ^{19}}

1.0 E 19 \cdot 2^{10} \cdot 5^{19} = 5^{19} \cdot 1.024 E 22

= - \frac{1}{5 ^{19} \cdot 1.024 E 22}

68 e^{- 180 \cdot (6.61 \cdot 1 0^{- 3})}

5.03 \cdot (1 0^{3})^{2}

e^{- 2 t} (sin^{2} (4 t) + cos (8 t))

3 (a)^{2} (3 b)

What is 3.2E-17*(-1.6)*10^{-19} ?
The solution to 3.2E-17*(-1.6)*10^{-19} is -1/(5^{19)*1.024E22}