What is \sqrt[3]{\sqrt[5]{64}} ?

The solution to \sqrt[3]{\sqrt[5]{64}} is \sqrt[5]{2^2}

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simplify \sqrt[3]{\sqrt[5]{64}}

simplify

Decimal Notation

1.31950 \dots

Solution steps

Apply radical rule:

= 2^{\frac{1}{3}} \cdot 2^{\frac{1}{15}}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

2^{\frac{1}{3}} \cdot 2^{\frac{1}{15}} = 2^{\frac{1}{3} + \frac{1}{15}}

= 2^{\frac{1}{3} + \frac{1}{15}}

\frac{1}{3} + \frac{1}{15} = \frac{2}{5}

= 2^{\frac{2}{5}}

[(x^{2} + 1)^{2022}]^{^{'}}

237 e^{- 1.018}

6321.1 \cdot 2.13 \cdot 1 0^{- 6}

\frac{6 ^{4}}{4 !} e^{- 6}

What is \sqrt[3]{\sqrt[5]{64}} ?
The solution to \sqrt[3]{\sqrt[5]{64}} is \sqrt[5]{2^2}