What are the solutions to the equation -x^2+5x=x^2-3x ?

The solutions to the equation -x^2+5x=x^2-3x are x=0,x=4

Find the zeros of -x^2+5x=x^2-3x

The zeros of -x^2+5x=x^2-3x are x=0,x=4

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- x^{2} + 5 x = x^{2} - 3 x

x = 0, x = 4

Solution steps

- x^{2} + 5 x = x^{2} - 3 x

Move

3 x

to the left side

- x^{2} + 8 x = x^{2}

Move

x^{2}

to the left side

- 2 x^{2} + 8 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 2 ) \cdot 0}{2 ( - 2 )}

8^{2} - 4 (- 2) \cdot 0 = 8

x_{1, 2} = \frac{- 8 \pm 8}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 8 + 8}{2 ( - 2 )}, x_{2} = \frac{- 8 - 8}{2 ( - 2 )}

x = \frac{- 8 + 8}{2 ( - 2 )} : 0

x = \frac{- 8 - 8}{2 ( - 2 )} : 4

The solutions to the quadratic equation are:

x = 0, x = 4

(2 w + 7) w = 99

∣ - 7 a ∣ = 28

- 25 x + 175 > 225

8000 = - 0.1 x^{2} + 90 x

9 < 5 x - 1 < 29

What are the solutions to the equation -x^2+5x=x^2-3x ?
The solutions to the equation -x^2+5x=x^2-3x are x=0,x=4
Find the zeros of -x^2+5x=x^2-3x
The zeros of -x^2+5x=x^2-3x are x=0,x=4