What is e^{-x}(e^x)(2xe^{x+x^2}) ?

The solution to e^{-x}(e^x)(2xe^{x+x^2}) is 2e^{x^2+x}x

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simplify e^{-x}(e^x)(2xe^{x+x^2})

simplify

e^{- x} (e^{x}) (2 x e^{x + x^{2}})

2 e^{x^{2} + x} x

Solution steps

e^{- x} (e^{x}) (2 x e^{x + x^{2}})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

e^{- x} e^{x} e^{x + x^{2}} = e^{- x + x + x + x^{2}}

= 2 x e^{- x + x + x + x^{2}}

Add similar elements:

- x + x + x = x

= 2 x e^{x + x^{2}}

e^{e^{x^{3}}} 6 x^{2} e^{x^{3}} d x

\frac{d}{d x} (x^{2} - y^{2})

p^{2} q^{2}

35 e^{- 0.015 \cdot 17.458}

3 2 x x

What is e^{-x}(e^x)(2xe^{x+x^2}) ?
The solution to e^{-x}(e^x)(2xe^{x+x^2}) is 2e^{x^2+x}x