What is ((2t^2-2t)^2)/((t^2+1)^2) ?

The solution to ((2t^2-2t)^2)/((t^2+1)^2) is ((2t^2-2t)^2)/((t^2+1)^2)

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simplify ((2t^2-2t)^2)/((t^2+1)^2)

simplify

\frac{( 2 t ^{2} - 2 t ) ^{2}}{( t ^{2} + 1 ) ^{2}}

\frac{( 2 t ^{2} - 2 t ) ^{2}}{( t ^{2} + 1 ) ^{2}}

Solution steps

\frac{( 2 t ^{2} - 2 t ) ^{2}}{( t ^{2} + 1 ) ^{2}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{( 2 t ^{2} - 2 t ) ^{2}}{( t ^{2} + 1 ) ^{2}} = (\frac{2 t ^{2} - 2 t}{t ^{2} + 1})^{2}

= (\frac{2 t ^{2} - 2 t}{t ^{2} + 1})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 2 t ^{2} - 2 t ) ^{2}}{( t ^{2} + 1 ) ^{2}}

20 \cdot (1.66 \cdot 1 0^{- 27})

e^{- 5 \cdot 0}

(4 - x^{2}) \cdot (x - 1)

2^{x} 0. 3^{x}

(1000) (2.2 \cdot 1 0^{- 5}) (10)

What is ((2t^2-2t)^2)/((t^2+1)^2) ?
The solution to ((2t^2-2t)^2)/((t^2+1)^2) is ((2t^2-2t)^2)/((t^2+1)^2)