What is 2te^{-2s}u(t-2) ?

The solution to 2te^{-2s}u(t-2) is (2tu(t-2))/(e^{2s)}

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simplify 2te^{-2s}u(t-2)

simplify

2 t e^{- 2 s} u (t - 2)

\frac{2 t u ( t - 2 )}{e ^{2 s}}

Solution steps

2 t e^{- 2 s} u (t - 2)

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= 2 \cdot \frac{1}{e ^{2 s}} t u (t - 2)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2 t u ( t - 2 )}{e ^{2 s}}

Multiply the numbers:

1 \cdot 2 = 2

= \frac{2 t u ( t - 2 )}{e ^{2 s}}

- 2 z y

(7.929 \cdot 1 0^{- 3}) (250)

- 100000 \cdot e^{- 0.05}

0.24 e^{- \frac{t}{0.6}}

1 0^{- l o g_{10} (x)}

What is 2te^{-2s}u(t-2) ?
The solution to 2te^{-2s}u(t-2) is (2tu(t-2))/(e^{2s)}