What are the solutions to the equation 3x^2-9x+6=0 ?

The solutions to the equation 3x^2-9x+6=0 are x=2,x=1

Find the zeros of 3x^2-9x+6=0

The zeros of 3x^2-9x+6=0 are x=2,x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} - 9 x + 6 = 0

x = 2, x = 1

Solution steps

3 x^{2} - 9 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 3 \cdot 6}{2 \cdot 3}

(- 9)^{2} - 4 \cdot 3 \cdot 6 = 3

x_{1, 2} = \frac{- ( - 9 ) \pm 3}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 3}{2 \cdot 3}, x_{2} = \frac{- ( - 9 ) - 3}{2 \cdot 3}

x = \frac{- ( - 9 ) + 3}{2 \cdot 3} : 2

x = \frac{- ( - 9 ) - 3}{2 \cdot 3} : 1

The solutions to the quadratic equation are:

x = 2, x = 1

∣ x - 5 ∣ \leq 2 x

∣ 3 x - 1 ∣ - 3 \leq \frac{x}{2} + 1

e^{1} - e^{0}

1 + (a - 3 b)^{3}

x + \frac{1}{4} = \frac{7}{8}

What are the solutions to the equation 3x^2-9x+6=0 ?
The solutions to the equation 3x^2-9x+6=0 are x=2,x=1
Find the zeros of 3x^2-9x+6=0
The zeros of 3x^2-9x+6=0 are x=2,x=1