What is x^2(x+1)^2(2x^2+2x-1) ?

The solution to x^2(x+1)^2(2x^2+2x-1) is x^2(x+1)^2(2x^2+2x-1)

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simplify x^2(x+1)^2(2x^2+2x-1)

simplify

x^{2} (x + 1)^{2} (2 x^{2} + 2 x - 1)

x^{2} (x + 1)^{2} (2 x^{2} + 2 x - 1)

Solution steps

x^{2} (x + 1)^{2} (2 x^{2} + 2 x - 1)

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

x^{2} (x + 1)^{2} = (x (x + 1))^{2}

= (x (x + 1))^{2} (2 x^{2} + 2 x - 1)

(x (x + 1))^{2} = x^{2} (x + 1)^{2}

= x^{2} (x + 1)^{2} (2 x^{2} + 2 x - 1)

- 1.4 e^{- 0.007 \cdot 100}

x \cdot \frac{1}{x} + 1

0.6 \cdot 1 \cdot 2 \frac{1.2 \cdot 1 \cdot 9.81}{9.81}

x^{2} - 4 \cdot 1 - x^{2}

6 a^{2} b^{5} c^{2} (8 a^{3} b^{2} - 7 a^{3} b c)

What is x^2(x+1)^2(2x^2+2x-1) ?
The solution to x^2(x+1)^2(2x^2+2x-1) is x^2(x+1)^2(2x^2+2x-1)