What is sqrt(n+1)*sqrt(n-1) ?

The solution to sqrt(n+1)*sqrt(n-1) is sqrt((n+1)(n-1))

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simplify sqrt(n+1)*sqrt(n-1)

simplify

n + 1 \cdot n - 1

(n + 1) (n - 1)

Solution steps

n + 1 n - 1

Apply radical rule:

a b = a \cdot b,

assuming

a \geq 0, b \geq 0

n + 1 n - 1 = (n + 1) (n - 1)

= (n + 1) (n - 1)

(2) \cdot e^{- 2}

4 π \cdot 1 0^{(- 7)}

0.18 \cdot 1 0^{- 5}

What is sqrt(n+1)*sqrt(n-1) ?
The solution to sqrt(n+1)*sqrt(n-1) is sqrt((n+1)(n-1))