What is completly(4y^{-10})(3y^6) ?

The solution to completly(4y^{-10})(3y^6) is (12ecl^2ompt)/(y^3)

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simplify completly(4y^{-10})(3y^6)

simplify

co m pl e tl y (4 y^{- 10}) (3 y^{6})

\frac{12 ec l ^{2} o m pt}{y ^{3}}

Solution steps

co m pl e tl y (4 y^{- 10}) (3 y^{6})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

ll = l^{1 + 1}

= co m p e t l^{1 + 1} y \cdot 4 y^{- 10} \cdot 3 y^{6}

Add the numbers:

1 + 1 = 2

= co m p e t l^{2} y \cdot 4 y^{- 10} \cdot 3 y^{6}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

y y^{- 10} y^{6} = y^{1 - 10 + 6}

= co m p e t l^{2} \cdot 4 \cdot 3 y^{1 - 10 + 6}

Add/Subtract the numbers:

1 - 10 + 6 = - 3

= co m p e t l^{2} \cdot 4 \cdot 3 y^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

y^{- 3} = \frac{1}{y ^{3}}

= 4 \cdot 3 ec l^{2} \frac{1}{y ^{3}} o m pt

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot co m p e t l ^{2} \cdot 4 \cdot 3}{y ^{3}}

Multiply the numbers:

1 \cdot 4 \cdot 3 = 12

= \frac{12 ec l ^{2} o m pt}{y ^{3}}

(sin (2 wt)) (e^{(- 3 t)})

(e^{- x}) (\frac{1}{2} e^{- x})

4.61 \cdot 1 0^{- 6}

e^{- 5110.353}

\frac{( 0.2 + x ) ^{2}}{( 0.2 - x ) ^{2}}

What is completly(4y^{-10})(3y^6) ?
The solution to completly(4y^{-10})(3y^6) is (12ecl^2ompt)/(y^3)