What is ((n-1)^2)/((2n+1)^2) ?

The solution to ((n-1)^2)/((2n+1)^2) is ((n-1)^2)/((2n+1)^2)

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simplify ((n-1)^2)/((2n+1)^2)

simplify

\frac{( n - 1 ) ^{2}}{( 2 n + 1 ) ^{2}}

\frac{( n - 1 ) ^{2}}{( 2 n + 1 ) ^{2}}

Solution steps

\frac{( n - 1 ) ^{2}}{( 2 n + 1 ) ^{2}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{( n - 1 ) ^{2}}{( 2 n + 1 ) ^{2}} = (\frac{n - 1}{2 n + 1})^{2}

= (\frac{n - 1}{2 n + 1})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( n - 1 ) ^{2}}{( 2 n + 1 ) ^{2}}

- 2 \cdot 1 0^{- 7} (1.2) 20 ln (21)

- \frac{π}{2} e^{- 3 \cdot 0.2}

(0.92 \cdot (z - 0.9048)) \cdot z^{- 1}

2.16 \cdot 1 0^{- 1}

(2 y + 20)^{\circ} (4 y - 80)^{\circ}

What is ((n-1)^2)/((2n+1)^2) ?
The solution to ((n-1)^2)/((2n+1)^2) is ((n-1)^2)/((2n+1)^2)