What is \sqrt[5]{2^x}*\sqrt[3]{4x=sqrt(8^{-x)}} ?

The solution to \sqrt[5]{2^x}*\sqrt[3]{4x=sqrt(8^{-x)}} is 2^{x/5}\sqrt[3]{4=xsqrt(8^{-x)}}

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simplify \sqrt[5]{2^x}*\sqrt[3]{4x=sqrt(8^{-x)}}

simplify

Solution steps

- 2 e^{- 2^{22.32}} 2. 3^{2}

2 (3 \cdot 2^{k})

\frac{e ^{2}}{2} (\frac{2}{e ^{2}})^{\frac{1}{2}}

(x^{'} x)^{- 1} x^{'} y

\frac{( - 4 π ^{2} ) ^{2}}{4 ^{2}} \cdot 0.06 3^{2}

What is \sqrt[5]{2^x}*\sqrt[3]{4x=sqrt(8^{-x)}} ?
The solution to \sqrt[5]{2^x}*\sqrt[3]{4x=sqrt(8^{-x)}} is 2^{x/5}\sqrt[3]{4=xsqrt(8^{-x)}}