What are the solutions to the equation 2x^2+3x=20 ?

The solutions to the equation 2x^2+3x=20 are x= 5/2 ,x=-4

Find the zeros of 2x^2+3x=20

The zeros of 2x^2+3x=20 are x= 5/2 ,x=-4

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2 x^{2} + 3 x = 20

x = \frac{5}{2}, x = - 4

Decimal Notation

x = 2.5, x = - 4

Solution steps

2 x^{2} + 3 x = 20

Move

20

to the left side

2 x^{2} + 3 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 ( - 20 )}{2 \cdot 2}

3^{2} - 4 \cdot 2 (- 20) = 13

x_{1, 2} = \frac{- 3 \pm 13}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 3 + 13}{2 \cdot 2}, x_{2} = \frac{- 3 - 13}{2 \cdot 2}

x = \frac{- 3 + 13}{2 \cdot 2} : \frac{5}{2}

x = \frac{- 3 - 13}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = - 4

\frac{17}{13} = \frac{u}{6}

2.1 (2.3 + 2.1 x) = 11.65 + x

\frac{4.8 \cdot 1 0 ^{- 7}}{1.6 \cdot 1 0 ^{- 11}}

\frac{12 k ^{2} - 20 k}{4 k}

2 5^{3}

What are the solutions to the equation 2x^2+3x=20 ?
The solutions to the equation 2x^2+3x=20 are x= 5/2 ,x=-4
Find the zeros of 2x^2+3x=20
The zeros of 2x^2+3x=20 are x= 5/2 ,x=-4