What is (x+2y)^2*(x^2-2xy+4y^2)^2 ?

The solution to (x+2y)^2*(x^2-2xy+4y^2)^2 is (x+2y)^2(x^2-2xy+4y^2)^2

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simplify (x+2y)^2*(x^2-2xy+4y^2)^2

simplify

(x + 2 y)^{2} \cdot (x^{2} - 2 x y + 4 y^{2})^{2}

(x + 2 y)^{2} (x^{2} - 2 x y + 4 y^{2})^{2}

Solution steps

(x + 2 y)^{2} (x^{2} - 2 x y + 4 y^{2})^{2}

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(x + 2 y)^{2} (x^{2} - 2 x y + 4 y^{2})^{2} = ((x + 2 y) (x^{2} - 2 x y + 4 y^{2}))^{2}

= ((x + 2 y) (x^{2} - 2 x y + 4 y^{2}))^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= (x + 2 y)^{2} (x^{2} - 2 x y + 4 y^{2})^{2}

(\frac{50}{2.447 \cdot 1 0 ^{- 4}}) \cdot 1 0^{- 6}

200 e^{- 0.02 x} \cdot x

1.68 \cdot 1 0^{- 8} [1 + 0.0068 (55 - 20)]

(1.7096 \cdot 1 0^{- 8}) (500)^{1.1146}

2.4 \cdot 1 0^{- 9}

What is (x+2y)^2*(x^2-2xy+4y^2)^2 ?
The solution to (x+2y)^2*(x^2-2xy+4y^2)^2 is (x+2y)^2(x^2-2xy+4y^2)^2