What is (2x+1)^2e^{-2(m+1)x} ?

The solution to (2x+1)^2e^{-2(m+1)x} is ((2x+1)^2)/(e^{2x(m+1))}

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simplify (2x+1)^2e^{-2(m+1)x}

simplify

(2 x + 1)^{2} e^{- 2 (m + 1) x}

\frac{( 2 x + 1 ) ^{2}}{e ^{2 x (m + 1)}}

Solution steps

(2 x + 1)^{2} e^{- 2 (m + 1) x}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{2 x (m + 1)}} (2 x + 1)^{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( 2 x + 1 ) ^{2}}{e ^{2 (m + 1) x}}

Multiply:

1 \cdot (2 x + 1)^{2} = (2 x + 1)^{2}

= \frac{( 2 x + 1 ) ^{2}}{e ^{2 x (m + 1)}}

0.1288 (\frac{1}{0.08205 \cdot 298.15})^{- 2}

e^{- 0.42 \cdot 8} \cdot 7

\frac{x + 1}{x + 2}

What is (2x+1)^2e^{-2(m+1)x} ?
The solution to (2x+1)^2e^{-2(m+1)x} is ((2x+1)^2)/(e^{2x(m+1))}