What is \sqrt[2n]{b}*\sqrt[2n]{b^n} ?

The solution to \sqrt[2n]{b}*\sqrt[2n]{b^n} is (b^{n+1})^{1/(2n)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify \sqrt[2n]{b}*\sqrt[2n]{b^n}

simplify

(b^{n + 1})^{\frac{1}{2 n}}

Solution steps

Apply radical rule:

assuming

a \geq 0, b \geq 0

= (b b^{n})^{\frac{1}{2 n}}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

b b^{n} = b^{1 + n}

= (b^{1 + n})^{\frac{1}{2 n}}

e^{2} \cdot e^{t}

(2.75 \cdot 1 0^{3}) (3 \cdot 1 0^{10})

8.9 \cdot 1 0^{- 2}

P^{1} (x^{1}, y^{1}) y P^{2} (x^{2}, y^{2})

[(- 8)^{5^{^{'}}}]^{2^{^{'}}}

What is \sqrt[2n]{b}*\sqrt[2n]{b^n} ?
The solution to \sqrt[2n]{b}*\sqrt[2n]{b^n} is (b^{n+1})^{1/(2n)}