What is (4cos(4)+ssin(4))/(s^2+16)e^{-3s} ?

The solution to (4cos(4)+ssin(4))/(s^2+16)e^{-3s} is (sin(4)s+4cos(4))/(e^{3s)(s^2+16)}

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simplify (4cos(4)+ssin(4))/(s^2+16)e^{-3s}

simplify

\frac{4 cos ( 4 ) + s sin ( 4 )}{s ^{2} + 16} e^{- 3 s}

\frac{sin ( 4 ) s + 4 cos ( 4 )}{e ^{3 s} ( s ^{2} + 16 )}

Solution steps

\frac{4 cos ( 4 ) + s sin ( 4 )}{s ^{2} + 16} e^{- 3 s}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{sin ( 4 ) s + 4 cos ( 4 )}{s ^{2} + 16} \cdot \frac{1}{e ^{3 s}}

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( 4 cos ( 4 ) + s sin ( 4 ) ) \cdot 1}{( s ^{2} + 16 ) e ^{3 s}}

(4 cos (4) + s sin (4)) \cdot 1 = 4 cos (4) + sin (4) s

= \frac{4 cos ( 4 ) + sin ( 4 ) s}{e ^{3 s} ( s ^{2} + 16 )}

\frac{1}{2} (5 \cdot 1 0^{- 2}) (2 π^{60})^{2} (0.06)^{2} (40)

12 \cdot 1 0^{- 7} \cdot 1481.48

53.5 \cdot 1. 5^{- 0.26}

\frac{d}{d x} ((z (x, y)) (x^{2} y^{2}))

2 (7.238 \cdot 1 0^{- 20})

What is (4cos(4)+ssin(4))/(s^2+16)e^{-3s} ?
The solution to (4cos(4)+ssin(4))/(s^2+16)e^{-3s} is (sin(4)s+4cos(4))/(e^{3s)(s^2+16)}