What is dx((2x+1)^4)/((3x-1)^4) ?

The solution to dx((2x+1)^4)/((3x-1)^4) is (dx(2x+1)^4)/((3x-1)^4)

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simplify dx((2x+1)^4)/((3x-1)^4)

simplify

d x \frac{( 2 x + 1 ) ^{4}}{( 3 x - 1 ) ^{4}}

\frac{d x ( 2 x + 1 ) ^{4}}{( 3 x - 1 ) ^{4}}

Solution steps

d x \frac{( 2 x + 1 ) ^{4}}{( 3 x - 1 ) ^{4}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{( 2 x + 1 ) ^{4}}{( 3 x - 1 ) ^{4}} = (\frac{2 x + 1}{3 x - 1})^{4}

= (\frac{2 x + 1}{3 x - 1})^{4} d x

(\frac{2 x + 1}{3 x - 1})^{4} = \frac{( 2 x + 1 ) ^{4}}{( 3 x - 1 ) ^{4}}

= \frac{( 2 x + 1 ) ^{4}}{( 3 x - 1 ) ^{4}} d x

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 2 x + 1 ) ^{4} d x}{( 3 x - 1 ) ^{4}}

e^{3} (e^{2})

9.4 \cdot 1 0^{- 2}

\frac{π}{4} \cdot 15. 3^{2} \cdot 15.3

- 0.3 (100) (100)^{5}

60 (2)^{- 0.02 (545)}

What is dx((2x+1)^4)/((3x-1)^4) ?
The solution to dx((2x+1)^4)/((3x-1)^4) is (dx(2x+1)^4)/((3x-1)^4)