What is 2.48(1.6*10^{-19}) ?

The solution to 2.48(1.6*10^{-19}) is (31)/(819200*5^{20)}

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simplify 2.48(1.6*10^{-19})

simplify

2.48 (1.6 \cdot 1 0^{- 19})

\frac{31}{819200 \cdot 5 ^{20}}

Decimal Notation

3.968 E - 19

Solution steps

2.48 (1.6 \cdot 1 0^{- 19})

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 19} = \frac{1}{1 0 ^{19}}

= 2.48 \cdot 1.6 \cdot \frac{1}{1 0 ^{19}}

1.6 \cdot \frac{1}{1 0 ^{19}} = \frac{1}{5 ^{20} \cdot 65536}

= 2.48 \cdot \frac{1}{5 ^{20} \cdot 65536}

2.48 \cdot \frac{1}{5 ^{20} \cdot 65536} = \frac{2.48}{5 ^{20} \cdot 65536}

= \frac{2.48}{5 ^{20} \cdot 65536}

\frac{2.48}{5 ^{20} \cdot 65536} = \frac{248}{6553600 \cdot 5 ^{20}}

= \frac{248}{6553600 \cdot 5 ^{20}}

Factor the number:

248 = 8 \cdot 31

= \frac{8 \cdot 31}{6553600 \cdot 5 ^{20}}

Factor the number:

6553600 = 8 \cdot 819200

= \frac{8 \cdot 31}{8 \cdot 819200 \cdot 5 ^{20}}

Cancel the common factor:

8

= \frac{31}{819200 \cdot 5 ^{20}}

⌊, ⌋ ⌊, ⌋ 32 m^{2}

7.24 \cdot 1 0^{- 4}

(52) (43)

2^{- l o g_{2} (5)}

(1 + 0.5 x)^{- 1}

What is 2.48(1.6*10^{-19}) ?
The solution to 2.48(1.6*10^{-19}) is (31)/(819200*5^{20)}