What are the solutions to the equation 14x^2-5x-1=0 ?

The solutions to the equation 14x^2-5x-1=0 are x= 1/2 ,x=-1/7

Find the zeros of 14x^2-5x-1=0

The zeros of 14x^2-5x-1=0 are x= 1/2 ,x=-1/7

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14 x^{2} - 5 x - 1 = 0

x = \frac{1}{2}, x = - \frac{1}{7}

Decimal Notation

x = 0.5, x = - 0.14285 \dots

Solution steps

14 x^{2} - 5 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 14 ( - 1 )}{2 \cdot 14}

(- 5)^{2} - 4 \cdot 14 (- 1) = 9

x_{1, 2} = \frac{- ( - 5 ) \pm 9}{2 \cdot 14}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 9}{2 \cdot 14}, x_{2} = \frac{- ( - 5 ) - 9}{2 \cdot 14}

x = \frac{- ( - 5 ) + 9}{2 \cdot 14} : \frac{1}{2}

x = \frac{- ( - 5 ) - 9}{2 \cdot 14} : - \frac{1}{7}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{1}{7}

- 2 (2 x + 9) > - 4 x + 9

x^{6} + 13 x^{3} + 30 = 0

(x) (1.06) (70000 - x) (1.085) = 70000 + 5000

(x + 9)^{2} (x + 4) (x - 1) > 0

10 + 6 x = 3 (2 x + 6) - 10

What are the solutions to the equation 14x^2-5x-1=0 ?
The solutions to the equation 14x^2-5x-1=0 are x= 1/2 ,x=-1/7
Find the zeros of 14x^2-5x-1=0
The zeros of 14x^2-5x-1=0 are x= 1/2 ,x=-1/7