What is e^{-0.1*(6/12)}[0.7564*3+0.2436*21] ?

The solution to e^{-0.1*(6/12)}[0.7564*3+0.2436*21] is 7.02463…

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simplify e^{-0.1(6/12)}[0.75643+0.2436*21]

simplify

e^{- 0.1 \cdot (\frac{6}{12})} [0.7564 \cdot 3 + 0.2436 \cdot 21]

7.02463 \dots

Solution steps

e^{- 0.1 (\frac{6}{12})} [0.7564 \cdot 3 + 0.2436 \cdot 21]

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{0.1 \cdot \frac{6}{12}}} [3 \cdot 0.7564 + 21 \cdot 0.2436]

\frac{1}{e ^{0.1 \cdot \frac{6}{12}}} = \frac{1}{e ^{0.05}}

= \frac{1}{e ^{0.05}} (3 \cdot 0.7564 + 21 \cdot 0.2436)

Multiply the numbers:

0.7564 \cdot 3 = 2.2692

= \frac{1}{e ^{0.05}} (21 \cdot 0.2436 + 2.2692)

Multiply the numbers:

0.2436 \cdot 21 = 5.1156

= \frac{1}{e ^{0.05}} (2.2692 + 5.1156)

Add the numbers:

2.2692 + 5.1156 = 7.3848

= 7.3848 \cdot \frac{1}{e ^{0.05}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 7.3848}{e ^{0.05}}

Multiply the numbers:

1 \cdot 7.3848 = 7.3848

= \frac{7.3848}{e ^{0.05}}

e^{0.05} = 1.05127 \dots

= \frac{7.3848}{1.05127 \dots}

Divide the numbers:

\frac{7.3848}{1.05127 \dots} = 7.02463 \dots

= 7.02463 \dots

- 3 m^{2} n^{2} (6 m^{3} n^{2} + 7 m^{2} n + 4)

13 e^{23} e^{- 3}

P^{1} (- 3, 4) P^{2} (- 6, - 2)

\frac{x - 1}{x ^{2} + 5 x + 6}

(5.48 \cdot 1 0^{2}) (7.287 \cdot 1 0^{5})

What is e^{-0.1*(6/12)}[0.7564*3+0.2436*21] ?
The solution to e^{-0.1*(6/12)}[0.7564*3+0.2436*21] is 7.02463…