simplify 2x2x

Solution

simplify

2 x^{\circ} 2 x

4 x^{\circ+ 1}

Solution steps

2 x^{\circ} \cdot 2 x

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

2 \cdot 2 = 2^{1 + 1}

= x^{\circ} \cdot 2^{1 + 1} x

Add the numbers:

1 + 1 = 2

= x^{\circ} \cdot 2^{2} x

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

x^{\circ} x = x^{\circ + 1}

= 2^{2} x^{\circ + 1}

2^{2} = 4

= 4 x^{\circ + 1}

5 co n sec (u) e n t e^{4}

e^{n} \cdot e^{1}

- 2 x (8 x^{2})

t e^{- 2 t} e^{2 t}

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