What is x5^{2x-1}sqrt(\sqrt[3]{25^{x^2-1/4)}} ?

The solution to x5^{2x-1}sqrt(\sqrt[3]{25^{x^2-1/4)}} is 5^{2x-1}xsqrt(5^{(4x^2-1)/6)}

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simplify x5^{2x-1}sqrt(\sqrt[3]{25^{x^2-1/4)}}

simplify

5^{2 x - 1} x 5^{\frac{4 x ^{2} - 1}{6}}

Solution steps

= x \cdot 5^{2 x - 1} 2 5^{\frac{4 x ^{2} - 1}{12}}

2 5^{\frac{4 x ^{2} - 1}{12}} = 5^{\frac{4 x ^{2} - 1}{6}}

= 5^{2 x - 1} x 5^{\frac{4 x ^{2} - 1}{6}}

2 \cdot 4 \cdot π \cdot 1 0^{- 7}

\frac{n}{n + n + n}

e^{- l n (x^{9})}

(e)^{2}

1429.5 (1.015)^{- 2}

What is x5^{2x-1}sqrt(\sqrt[3]{25^{x^2-1/4)}} ?
The solution to x5^{2x-1}sqrt(\sqrt[3]{25^{x^2-1/4)}} is 5^{2x-1}xsqrt(5^{(4x^2-1)/6)}