What is 2(2*1^2-1)e^{-1^2} ?

The solution to 2(2*1^2-1)e^{-1^2} is 2/e

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simplify 2(2*1^2-1)e^{-1^2}

simplify

2 (2 \cdot 1^{2} - 1) e^{- 1^{2}}

\frac{2}{e}

Decimal Notation

0.73575 \dots

Solution steps

2 (2 \cdot 1^{2} - 1) e^{- 1^{2}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= 2 \cdot \frac{1}{e ^{1^{2}}} (1^{2} \cdot 2 - 1)

Apply rule

1^{a} = 1

1^{2} = 1

= 2 \cdot \frac{1}{e ^{1}} (2 \cdot 1 - 1)

Multiply the numbers:

2 \cdot 1 = 2

= 2 \cdot \frac{1}{e ^{1}} (2 - 1)

Apply rule

a^{1} = a

e^{1} = e

= 2 \cdot \frac{1}{e} (2 - 1)

Subtract the numbers:

2 - 1 = 1

= 2 \cdot 1 \cdot \frac{1}{e}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= 1 \cdot \frac{1 \cdot 2}{e}

Multiply the numbers:

1 \cdot 2 = 2

= 1 \cdot \frac{2}{e}

Multiply:

1 \cdot \frac{2}{e} = \frac{2}{e}

= \frac{2}{e}

e^{- 2 l n (50 + t)}

1.00 1^{- 500} \cdot (\frac{1}{0.001})

(x y^{4} z^{3}) (3 x^{3} y^{4} z)

3.1 \cdot 1 0^{- 1}

e^{- 0.006}