What are the solutions to the equation 10x^2-16x+5=0 ?

The solutions to the equation 10x^2-16x+5=0 are x=(8+sqrt(14))/(10),x=(8-sqrt(14))/(10)

Find the zeros of 10x^2-16x+5=0

The zeros of 10x^2-16x+5=0 are x=(8+sqrt(14))/(10),x=(8-sqrt(14))/(10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

10 x^{2} - 16 x + 5 = 0

x = \frac{8 + 14}{10}, x = \frac{8 - 14}{10}

Decimal Notation

x = 1.17416 \dots, x = 0.42583 \dots

Solution steps

10 x^{2} - 16 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 10 \cdot 5}{2 \cdot 10}

(- 16)^{2} - 4 \cdot 10 \cdot 5 = 214

x_{1, 2} = \frac{- ( - 16 ) \pm 2 14}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 2 14}{2 \cdot 10}, x_{2} = \frac{- ( - 16 ) - 2 14}{2 \cdot 10}

x = \frac{- ( - 16 ) + 2 14}{2 \cdot 10} : \frac{8 + 14}{10}

x = \frac{- ( - 16 ) - 2 14}{2 \cdot 10} : \frac{8 - 14}{10}

The solutions to the quadratic equation are:

x = \frac{8 + 14}{10}, x = \frac{8 - 14}{10}

w + 50 > 8 w + 78 or \frac{- 89 w + 13}{2} < 5

32 t - 0.8 t^{2} = 160

2 x^{2} - 5 x + 4 = 0

8 - 11

\frac{\frac{5}{x} + \frac{1}{2 y}}{\frac{1}{2}}

What are the solutions to the equation 10x^2-16x+5=0 ?
The solutions to the equation 10x^2-16x+5=0 are x=(8+sqrt(14))/(10),x=(8-sqrt(14))/(10)
Find the zeros of 10x^2-16x+5=0
The zeros of 10x^2-16x+5=0 are x=(8+sqrt(14))/(10),x=(8-sqrt(14))/(10)