What is 8(2+x-x^2)e^{-2x} ?

The solution to 8(2+x-x^2)e^{-2x} is (8(-x^2+x+2))/(e^{2x)}

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simplify 8(2+x-x^2)e^{-2x}

simplify

8 (2 + x - x^{2}) e^{- 2 x}

\frac{8 ( - x ^{2} + x + 2 )}{e ^{2 x}}

Solution steps

8 (2 + x - x^{2}) e^{- 2 x}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= 8 \cdot \frac{1}{e ^{2 x}} (- x^{2} + x + 2)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 8 ( 2 + x - x ^{2} )}{e ^{2 x}}

Multiply the numbers:

1 \cdot 8 = 8

= \frac{8 ( - x ^{2} + x + 2 )}{e ^{2 x}}

2 t - 1 \cdot t - 1

5^{5} \cdot 2^{5}

11.7 \cdot 1 0^{- 7} \cdot 1.15 \cdot 43

1.05 \cdot 1 0^{- 6}

3 e^{- 3} (1 - 3)

What is 8(2+x-x^2)e^{-2x} ?
The solution to 8(2+x-x^2)e^{-2x} is (8(-x^2+x+2))/(e^{2x)}