What is product^{0.12}t^3(5t^5-2) ?

The solution to product^{0.12}t^3(5t^5-2) is cprot^{3.12}du(5t^5-2)

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simplify product^{0.12}t^3(5t^5-2)

simplify

p ro d u c t^{0.12} t^{3} (5 t^{5} - 2)

c p ro t^{3.12} d u (5 t^{5} - 2)

Solution steps

p ro d u c t^{0.12} t^{3} (5 t^{5} - 2)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

t^{0.12} t^{3} = t^{0.12 + 3}

= p ro d u c t^{0.12 + 3} (5 t^{5} - 2)

Add the numbers:

0.12 + 3 = 3.12

= p ro d u c t^{3.12} (5 t^{5} - 2)

425 x x

88 e n t r e^{13}

0.5 5^{3} \cdot 4 \cdot 0.55 \cdot 0.45

2^{2} (e^{- \frac{2}{2}})

(4 - 3 x)^{- \frac{1}{2}}

What is product^{0.12}t^3(5t^5-2) ?
The solution to product^{0.12}t^3(5t^5-2) is cprot^{3.12}du(5t^5-2)