What is (8.987*10^9)(8*10^{-12}) ?

The solution to (8.987*10^9)(8*10^{-12}) is 0.071896

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simplify (8.98710^9)(810^{-12})

simplify

(8.987 \cdot 1 0^{9}) (8 \cdot 1 0^{- 12})

0.071896

Solution steps

(8.987 \cdot 1 0^{9}) (8 \cdot 1 0^{- 12})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

1 0^{9} \cdot 1 0^{- 12} = 1 0^{9 - 12}

= 8.987 \cdot 8 \cdot 1 0^{9 - 12}

Subtract the numbers:

9 - 12 = - 3

= 8.987 \cdot 8 \cdot 1 0^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 3} = \frac{1}{1 0 ^{3}}

= 8 \cdot 8.987 \cdot \frac{1}{1 0 ^{3}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= 8.987 \cdot \frac{1 \cdot 8}{1 0 ^{3}}

\frac{1 \cdot 8}{1 0 ^{3}} = \frac{1}{125}

= 8.987 \cdot \frac{1}{125}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 8.987}{125}

Multiply the numbers:

1 \cdot 8.987 = 8.987

= \frac{8.987}{125}

Divide the numbers:

\frac{8.987}{125} = 0.071896

= 0.071896

- 2 (x^{2} - 9) (2 x)

(0.4)^{2} \cdot (4)^{- 2} \cdot (3)^{- 1}

(6 x^{4} y^{8}) (3 x^{3} y)

- e^{x} \cdot e^{- 4 x}

(1500 t + 1) e^{- 150 t} \cdot 40 e^{- 150 t}

What is (8.987*10^9)(8*10^{-12}) ?
The solution to (8.987*10^9)(8*10^{-12}) is 0.071896