What is 275500(1+(0.11)/2)^{-10}(1+0.11(11/12)) ?

The solution to 275500(1+(0.11)/2)^{-10}(1+0.11(11/12)) is (25^{10}*9.76932E14)/(3*211^{10)}

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simplify 275500(1+(0.11)/2)^{-10}(1+0.11(11/12))

simplify

275500 (1 + \frac{0.11}{2})^{- 10} (1 + 0.11 (\frac{11}{12}))

\frac{2 5 ^{10} \cdot 9.76932 E 14}{3 \cdot 21 1 ^{10}}

Decimal Notation

177549.14219 \dots

Solution steps

275500 (1 + \frac{0.11}{2})^{- 10} (1 + 0.11 (\frac{11}{12}))

(1 + \frac{0.11}{2})^{- 10} = \frac{20 0 ^{10}}{21 1 ^{10}}

= 275500 \cdot \frac{20 0 ^{10}}{21 1 ^{10}} (1 + 0.11 \cdot \frac{11}{12})

1 + 0.11 \cdot \frac{11}{12} = \frac{1321}{1200}

= 275500 \cdot \frac{20 0 ^{10}}{21 1 ^{10}} \cdot \frac{1321}{1200}

275500 \cdot \frac{20 0 ^{10}}{21 1 ^{10}} \cdot \frac{1321}{1200} = \frac{2 5 ^{10} \cdot 9.76932 E 14}{3 \cdot 21 1 ^{10}}

= \frac{2 5 ^{10} \cdot 9.76932 E 14}{3 \cdot 21 1 ^{10}}

\frac{x - 2}{5 - x}

\frac{x - 1}{x ^{2} - 5 x + 6}

e^{2 x} \cdot e^{- y}

2 \cdot 1 0^{- 7} 0.45 \cdot 0.45 \cdot ln (2)

What is 275500(1+(0.11)/2)^{-10}(1+0.11(11/12)) ?
The solution to 275500(1+(0.11)/2)^{-10}(1+0.11(11/12)) is (25^{10}*9.76932E14)/(3*211^{10)}