What is (6.4)(8.85(10^{-12})2.4)(5/3) ?

The solution to (6.4)(8.85(10^{-12})2.4)(5/3) is 177/781250000000

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simplify (6.4)(8.85(10^{-12})2.4)(5/3)

simplify

(6.4) (8.85 (1 0^{- 12}) 2.4) (\frac{5}{3})

\frac{177}{781250000000}

Decimal Notation

2.2656 E - 10

Solution steps

(6.4) (8.85 (1 0^{- 12}) \cdot 2.4) (\frac{5}{3})

6.4 = \frac{32}{5}

= \frac{32}{5} \cdot 8.85 \cdot 1 0^{- 12} \cdot 2.4 \cdot \frac{5}{3}

8.85 = \frac{177}{20}

= \frac{32}{5} \cdot \frac{177}{20} \cdot 1 0^{- 12} \cdot 2.4 \cdot \frac{5}{3}

2.4 = \frac{12}{5}

= \frac{32}{5} \cdot \frac{177}{20} \cdot 1 0^{- 12} \cdot \frac{12}{5} \cdot \frac{5}{3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 12} = \frac{1}{1 0 ^{12}}

= \frac{32}{5} \cdot \frac{177}{20} \cdot \frac{1}{1 0 ^{12}} \cdot \frac{12}{5} \cdot \frac{5}{3}

Cross-cancel common factor:

5

= \frac{32}{3} \cdot \frac{177}{20} \cdot \frac{1}{1 0 ^{12}} \cdot \frac{12}{5}

\frac{32}{3} \cdot \frac{177}{20} \cdot \frac{1}{1 0 ^{12}} \cdot \frac{12}{5} = \frac{177}{781250000000}

= \frac{177}{781250000000}

2 (b^{- 1}) (b - 2 e)^{\frac{1}{2}}

θ^{4} e^{- 130 θ}

2.3126 \cdot 1 0^{- 8} (2)

L^{0.3} K^{0.3}

What is (6.4)(8.85(10^{-12})2.4)(5/3) ?
The solution to (6.4)(8.85(10^{-12})2.4)(5/3) is 177/781250000000