What is the (x^{2/3})^' ?

The (x^{2/3})^' is 2/(3x^{1/3)}

What is the first (x^{2/3})^' ?

The first (x^{2/3})^' is 2/(3x^{1/3)}

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(x^{\frac{2}{3}})^{^{'}}

\frac{2}{3 x ^{\frac{1}{3}}}

Solution steps

(x^{\frac{2}{3}})^{'}

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{2}{3} x^{\frac{2}{3} - 1}

Simplify

\frac{2}{3} x^{\frac{2}{3} - 1} : \frac{2}{3 x ^{\frac{1}{3}}}

= \frac{2}{3 x ^{\frac{1}{3}}}

(e^{(\frac{2 π}{6})})^{2}

e^{\frac{1}{x - 2}} (e^{- 1})

9 \cdot 1 0^{9} (2.2188 \cdot 1 0^{- 6})