What is factor x^4-x^3-8x^2+12x ?

The solution to factor x^4-x^3-8x^2+12x is x(x-2)^2(x+3)

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factor x^4-x^3-8x^2+12x

factor

x^{4} - x^{3} - 8 x^{2} + 12 x

x (x - 2)^{2} (x + 3)

Solution steps

x^{4} - x^{3} - 8 x^{2} + 12 x

Factor out common term

x : x (x^{3} - x^{2} - 8 x + 12)

= x (x^{3} - x^{2} - 8 x + 12)

Factor

x^{3} - x^{2} - 8 x + 12 : (x - 2) (x - 2) (x + 3)

= x (x - 2) (x - 2) (x + 3)

Apply exponent rule:

aa = a^{2}

(x - 2) (x - 2) = (x - 2)^{2}

= x (x - 2)^{2} (x + 3)

\frac{3 ( 2 ^{2} c ^{4} d ^{5} ) ^{3}}{( 2 c d ^{2} ) ^{4}}

\frac{a ^{\frac{1}{3}}}{a ^{\frac{1}{4}}}

3 x - 27 = 0

- 22 \leq 2 x - 1 \leq 1

\frac{7 π}{6} - π

What is factor x^4-x^3-8x^2+12x ?
The solution to factor x^4-x^3-8x^2+12x is x(x-2)^2(x+3)