What is (3(2^2c^4d^5)^3)/((2cd^2)^4) ?

The solution to (3(2^2c^4d^5)^3)/((2cd^2)^4) is 12c^8d^7

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simplify (3(2^2c^4d^5)^3)/((2cd^2)^4)

simplify

\frac{3 ( 2 ^{2} c ^{4} d ^{5} ) ^{3}}{( 2 c d ^{2} ) ^{4}}

12 c^{8} d^{7}

Solution steps

\frac{3 ( 2 ^{2} c ^{4} d ^{5} ) ^{3}}{( 2 c d ^{2} ) ^{4}}

Simplify

(2^{2} c^{4} d^{5})^{3} : 64 c^{12} d^{15}

= \frac{3 \cdot 64 c ^{12} d ^{15}}{( 2 c d ^{2} ) ^{4}}

Simplify

(2 c d^{2})^{4} : 2^{4} c^{4} d^{8}

= \frac{3 \cdot 64 c ^{12} d ^{15}}{2 ^{4} c ^{4} d ^{8}}

Factor the number:

64 = 2^{6}

= \frac{3 \cdot 2 ^{6} c ^{12} d ^{15}}{2 ^{4} c ^{4} d ^{8}}

\frac{2 ^{6}}{2 ^{4}} = 2^{2}

= \frac{3 \cdot 2 ^{2} c ^{12} d ^{15}}{c ^{4} d ^{8}}

Simplify

\frac{c ^{12}}{c ^{4}} : c^{8}

= \frac{3 \cdot 2 ^{2} c ^{8} d ^{15}}{d ^{8}}

Simplify

\frac{d ^{15}}{d ^{8}} : d^{7}

= 3 \cdot 2^{2} c^{8} d^{7}

Simplify

3 \cdot 2^{2} c^{8} d^{7} : 12 c^{8} d^{7}

= 12 c^{8} d^{7}

\frac{a ^{\frac{1}{3}}}{a ^{\frac{1}{4}}}

3 x - 27 = 0

- 22 \leq 2 x - 1 \leq 1

\frac{7 π}{6} - π

(\frac{1}{10})^{2 x} > 12

What is (3(2^2c^4d^5)^3)/((2cd^2)^4) ?
The solution to (3(2^2c^4d^5)^3)/((2cd^2)^4) is 12c^8d^7