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Popular >

(e^{(-1)/(x^2)})^'

Solution

(e^{\frac{- 1}{x ^{2}}})^{^{'}}

Solution

\frac{2 e ^{- \frac{1}{x ^{2}}}}{x ^{3}}

Solution steps

(e^{\frac{- 1}{x ^{2}}})^{'}

Simplify

e^{\frac{- 1}{x ^{2}}} : e^{- \frac{1}{x ^{2}}}

= (e^{- \frac{1}{x ^{2}}})^{^{'}}

Apply the chain rule:

e^{- \frac{1}{x ^{2}}} (- \frac{1}{x ^{2}})^{'}

= e^{- \frac{1}{x ^{2}}} (- \frac{1}{x ^{2}})^{'}

(- \frac{1}{x ^{2}})^{'} = \frac{2}{x ^{3}}

= e^{- \frac{1}{x ^{2}}} \frac{2}{x ^{3}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 e ^{- \frac{1}{x ^{2}}}}{x ^{3}}

Popular Examples

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\frac{1}{2 π} e^{- \frac{2 ^{2}}{2}}

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(0.018) \cdot (4.68 \cdot 1 0^{- 6})

simplify (h/(2pi))^2*pi^2 simplify

(\frac{h}{2 π})^{2} \cdot π^{2}

simplify (sqrt(19))/(sqrt(13))simplify

\frac{19}{13}

Frequently Asked Questions (FAQ)

What is the (e^{(-1)/(x^2)})^' ?
The (e^{(-1)/(x^2)})^' is (2e^{-1/(x^2)})/(x^3)
What is the first (e^{(-1)/(x^2)})^' ?
The first (e^{(-1)/(x^2)})^' is (2e^{-1/(x^2)})/(x^3)