What is (x^2-2x+5)^2(x+2)^2(x-1) ?

The solution to (x^2-2x+5)^2(x+2)^2(x-1) is (x+2)^2(x-1)(x^2-2x+5)^2

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simplify (x^2-2x+5)^2(x+2)^2(x-1)

simplify

(x^{2} - 2 x + 5)^{2} (x + 2)^{2} (x - 1)

(x + 2)^{2} (x - 1) (x^{2} - 2 x + 5)^{2}

Solution steps

(x^{2} - 2 x + 5)^{2} (x + 2)^{2} (x - 1)

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(x^{2} - 2 x + 5)^{2} (x + 2)^{2} = ((x^{2} - 2 x + 5) (x + 2))^{2}

= ((x^{2} - 2 x + 5) (x + 2))^{2} (x - 1)

((x^{2} - 2 x + 5) (x + 2))^{2} = (x^{2} - 2 x + 5)^{2} (x + 2)^{2}

= (x^{2} - 2 x + 5)^{2} (x + 2)^{2} (x - 1)

840000 e^{- 0.16 \cdot 3}

e^{- (0.1)}

(4 r^{71} s^{8} t^{69} u) (4 r^{73} s t^{57} u)

(4.5 \cdot 1 0^{4}) \cdot (6.2 \cdot 1 0^{3})

e^{(- \frac{π}{2})}

What is (x^2-2x+5)^2(x+2)^2(x-1) ?
The solution to (x^2-2x+5)^2(x+2)^2(x-1) is (x+2)^2(x-1)(x^2-2x+5)^2