What is 1/2*1/2 (16-x^2)^{-1/2}*(2x) ?

The solution to 1/2*1/2 (16-x^2)^{-1/2}*(2x) is x/(2(-x^2+16)^{1/2)}

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simplify 1/21/2 (16-x^2)^{-1/2}(2x)

simplify

\frac{1}{2} \cdot \frac{1}{2} (16 - x^{2})^{- \frac{1}{2}} \cdot (2 x)

\frac{x}{2 ( - x ^{2} + 16 ) ^{\frac{1}{2}}}

Solution steps

\frac{1}{2} \cdot \frac{1}{2} (16 - x^{2})^{- \frac{1}{2}} (2 x)

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= 2 \cdot \frac{1}{2} \cdot \frac{1}{2} \cdot \frac{1}{( - x ^{2} + 16 ) ^{\frac{1}{2}}} x

Multiply fractions:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{1 \cdot 1 \cdot 1 \cdot 2 x}{2 \cdot 2 ( 16 - x ^{2} ) ^{\frac{1}{2}}}

Cancel the common factor:

2

= \frac{1 \cdot 1 \cdot 1 \cdot x}{2 ( 16 - x ^{2} ) ^{\frac{1}{2}}}

Multiply:

1 \cdot 1 \cdot 1 \cdot x = x

= \frac{x}{2 ( - x ^{2} + 16 ) ^{\frac{1}{2}}}

\frac{1}{2} x^{4} (16 x^{5})

(3 r^{4}) (12 r^{6})

1.75 \cdot 1 0^{- 5} \cdot 0.1

C^{\circ} r d I^{9} h z E^{906} L E h h^{9} h

What is 1/2*1/2 (16-x^2)^{-1/2}*(2x) ?
The solution to 1/2*1/2 (16-x^2)^{-1/2}*(2x) is x/(2(-x^2+16)^{1/2)}