What is expand sqrt(((ln(1/4))^2)/(pi^2+(ln(1/4))^2)) ?

The solution to expand sqrt(((ln(1/4))^2)/(pi^2+(ln(1/4))^2)) is (2ln(2))/(sqrt(4ln^2(2)+pi^2))

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expand sqrt(((ln(1/4))^2)/(pi^2+(ln(1/4))^2))

expand

\frac{( ln ( \frac{1}{4} ) ) ^{2}}{π ^{2} + ( ln ( \frac{1}{4} ) ) ^{2}}

\frac{2 ln ( 2 )}{4 ln ^{2} ( 2 ) + π ^{2}}

Decimal Notation

0.40371 \dots

Solution steps

\frac{( ln ( \frac{1}{4} ) ) ^{2}}{π ^{2} + ( ln ( \frac{1}{4} ) ) ^{2}}

Apply radical rule:

\frac{a}{b} = \frac{a}{b}

\frac{( ln ( \frac{1}{4} ) ) ^{2}}{π ^{2} + ( ln ( \frac{1}{4} ) ) ^{2}} = \frac{( ln ( \frac{1}{4} ) ) ^{2}}{π ^{2} + ( ln ( \frac{1}{4} ) ) ^{2}}

= \frac{( ln ( \frac{1}{4} ) ) ^{2}}{π ^{2} + ( ln ( \frac{1}{4} ) ) ^{2}}

(ln (\frac{1}{4}))^{2} = 2 ln (2)

= \frac{2 ln ( 2 )}{π ^{2} + ( ln ( \frac{1}{4} ) ) ^{2}}

π^{2} + (ln (\frac{1}{4}))^{2} = π^{2} + 4 ln^{2} (2)

= \frac{2 ln ( 2 )}{π ^{2} + 4 ln ^{2} ( 2 )}

(15 a^{2} b^{3} c^{2}) (2 a b^{3} c^{5})

x - 7 \cdot x + 1

\frac{1875.3944 1 ^{2}}{1239.842} \cdot 5.79 \cdot 1 0^{- 5}

e^{- A t}

What is expand sqrt(((ln(1/4))^2)/(pi^2+(ln(1/4))^2)) ?
The solution to expand sqrt(((ln(1/4))^2)/(pi^2+(ln(1/4))^2)) is (2ln(2))/(sqrt(4ln^2(2)+pi^2))