What are the solutions to the equation x^2+8=-9x ?

The solutions to the equation x^2+8=-9x are x=-1,x=-8

Find the zeros of x^2+8=-9x

The zeros of x^2+8=-9x are x=-1,x=-8

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x^{2} + 8 = - 9 x

x = - 1, x = - 8

Solution steps

x^{2} + 8 = - 9 x

Move

9 x

to the left side

x^{2} + 8 + 9 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 9 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 8 = 7

x_{1, 2} = \frac{- 9 \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 7}{2 \cdot 1}, x_{2} = \frac{- 9 - 7}{2 \cdot 1}

x = \frac{- 9 + 7}{2 \cdot 1} : - 1

x = \frac{- 9 - 7}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = - 1, x = - 8

4 x^{2} - 16 x + 12 = 0

(x - 1)^{2} - 1 = 0

(x + 2) (x + 5) = 28

15 f^{2} + 2 f - 45

\frac{8 k + 9}{18} - \frac{2 k + 1}{18}

What are the solutions to the equation x^2+8=-9x ?
The solutions to the equation x^2+8=-9x are x=-1,x=-8
Find the zeros of x^2+8=-9x
The zeros of x^2+8=-9x are x=-1,x=-8