What are the solutions to the equation 8x^2+10x-7=0 ?

The solutions to the equation 8x^2+10x-7=0 are x= 1/2 ,x=-7/4

Find the zeros of 8x^2+10x-7=0

The zeros of 8x^2+10x-7=0 are x= 1/2 ,x=-7/4

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8 x^{2} + 10 x - 7 = 0

x = \frac{1}{2}, x = - \frac{7}{4}

Solution steps

8 x^{2} + 10 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 8 ( - 7 )}{2 \cdot 8}

1 0^{2} - 4 \cdot 8 (- 7) = 18

x_{1, 2} = \frac{- 10 \pm 18}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 10 + 18}{2 \cdot 8}, x_{2} = \frac{- 10 - 18}{2 \cdot 8}

x = \frac{- 10 + 18}{2 \cdot 8} : \frac{1}{2}

x = \frac{- 10 - 18}{2 \cdot 8} : - \frac{7}{4}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{7}{4}

2 (x - 2) = 1 - 3 (x - 4) - 2

24 x^{2} - 44 x + 12

\frac{27 x ^{4} y ^{6}}{9 x ^{5} y ^{2}}

∣ 2 x + 9 ∣ = 7

2 (\frac{π}{4})

What are the solutions to the equation 8x^2+10x-7=0 ?
The solutions to the equation 8x^2+10x-7=0 are x= 1/2 ,x=-7/4
Find the zeros of 8x^2+10x-7=0
The zeros of 8x^2+10x-7=0 are x= 1/2 ,x=-7/4