What are the solutions to the equation (x-3)^2-4=0 ?

The solutions to the equation (x-3)^2-4=0 are x=5,x=1

Find the zeros of (x-3)^2-4=0

The zeros of (x-3)^2-4=0 are x=5,x=1

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(x - 3)^{2} - 4 = 0

x = 5, x = 1

Solution steps

(x - 3)^{2} - 4 = 0

Move

4

to the right side

(x - 3)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 4 : x = 5

Solve

x - 3 = - 4 : x = 1

The solutions to the quadratic equation are:

x = 5, x = 1

∣ x + 1 ∣ = ∣ 2 - x ∣

- 2 m < 6

6 - (- 5)

10 - 9 y \geq - 2 y^{2}

4 x^{3} + 8 x^{2} + 5 x + 1

What are the solutions to the equation (x-3)^2-4=0 ?
The solutions to the equation (x-3)^2-4=0 are x=5,x=1
Find the zeros of (x-3)^2-4=0
The zeros of (x-3)^2-4=0 are x=5,x=1