What is the (e^{3x^2})^' ?

The (e^{3x^2})^' is e^{3x^2}*6x

What is the first (e^{3x^2})^' ?

The first (e^{3x^2})^' is e^{3x^2}*6x

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(e^{3 x^{2}})^{^{'}}

e^{3 x^{2}} \cdot 6 x

Solution steps

(e^{3 x^{2}})^{'}

Apply the chain rule:

e^{3 x^{2}} (3 x^{2})^{'}

= e^{3 x^{2}} (3 x^{2})^{'}

(3 x^{2})^{'} = 6 x

= e^{3 x^{2}} \cdot 6 x

e^{- 3.7} \cdot 3. 7^{2}

(e^{3 t})^{3} \cdot \frac{s - 4}{s + 10}

e^{- 12 (1 - 0.75) 0.5}

3 e^{- 0.001 (\frac{2.5}{12})}

t e^{- 3 t} sin (2 x)