What is e^{-2t}cos(pi*t*u(t-1)) ?

The solution to e^{-2t}cos(pi*t*u(t-1)) is (cos(pitu(t-1)))/(e^{2t)}

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simplify e^{-2t}cos(pitu(t-1))

simplify

e^{- 2 t} cos (π \cdot t \cdot u (t - 1))

\frac{cos ( π t u ( t - 1 ) )}{e ^{2 t}}

Solution steps

e^{- 2 t} cos (π t u (t - 1))

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{2 t}} cos (π t u (t - 1))

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot cos ( π t u ( t - 1 ) )}{e ^{2 t}}

Multiply:

1 \cdot cos (π t u (t - 1)) = cos (π t u (t - 1))

= \frac{cos ( π t u ( t - 1 ) )}{e ^{2 t}}

e^{- 0.1 (10)}

(35) (55)

x^{- \frac{1}{2}} \cdot 5 x^{6}

2 (a + b) (a - b)

(z + 1)^{2} (z - 1)^{2} (z^{2} + 1)

What is e^{-2t}cos(pi*t*u(t-1)) ?
The solution to e^{-2t}cos(pi*t*u(t-1)) is (cos(pitu(t-1)))/(e^{2t)}