What are the solutions to the equation (3x-4)^2=18 ?

The solutions to the equation (3x-4)^2=18 are x=(3sqrt(2)+4)/3 ,x=(-3sqrt(2)+4)/3

Find the zeros of (3x-4)^2=18

The zeros of (3x-4)^2=18 are x=(3sqrt(2)+4)/3 ,x=(-3sqrt(2)+4)/3

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(3 x - 4)^{2} = 18

x = \frac{3 2 + 4}{3}, x = \frac{- 3 2 + 4}{3}

Solution steps

(3 x - 4)^{2} = 18

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 4 = 18 : x = \frac{3 2 + 4}{3}

Solve

3 x - 4 = - 18 : x = \frac{- 3 2 + 4}{3}

The solutions to the quadratic equation are:

x = \frac{3 2 + 4}{3}, x = \frac{- 3 2 + 4}{3}

a^{3} - 1

n - 14 = 11

∣ 4 y - 1 ∣ \geq 10

w^{2} - 9 w x

What are the solutions to the equation (3x-4)^2=18 ?
The solutions to the equation (3x-4)^2=18 are x=(3sqrt(2)+4)/3 ,x=(-3sqrt(2)+4)/3
Find the zeros of (3x-4)^2=18
The zeros of (3x-4)^2=18 are x=(3sqrt(2)+4)/3 ,x=(-3sqrt(2)+4)/3