What are the solutions to the equation a^2-12a+35=0 ?

The solutions to the equation a^2-12a+35=0 are a=7,a=5

Find the zeros of a^2-12a+35=0

The zeros of a^2-12a+35=0 are a=7,a=5

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a^{2} - 12 a + 35 = 0

a = 7, a = 5

Solution steps

a^{2} - 12 a + 35 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 35}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 35 = 2

a_{1, 2} = \frac{- ( - 12 ) \pm 2}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 12 ) + 2}{2 \cdot 1}, a_{2} = \frac{- ( - 12 ) - 2}{2 \cdot 1}

a = \frac{- ( - 12 ) + 2}{2 \cdot 1} : 7

a = \frac{- ( - 12 ) - 2}{2 \cdot 1} : 5

The solutions to the quadratic equation are:

a = 7, a = 5

3 x - 1 \leq \frac{7}{2} x < 12 x + 2

\frac{5 x ^{7} y ^{8}}{x ^{2} y ^{8}}

\frac{3 m ^{- 4}}{m ^{3}}

- 2 x y^{2} - 4 x y + 6 x y^{2}

3 x^{2} - 3 y^{2}

What are the solutions to the equation a^2-12a+35=0 ?
The solutions to the equation a^2-12a+35=0 are a=7,a=5
Find the zeros of a^2-12a+35=0
The zeros of a^2-12a+35=0 are a=7,a=5