What is ((e^x-e^{-x})/2)^{-1} ?

The solution to ((e^x-e^{-x})/2)^{-1} is 2/(e^x-e^{-x)}

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simplify ((e^x-e^{-x})/2)^{-1}

simplify

(\frac{e ^{x} - e ^{- x}}{2})^{- 1}

\frac{2}{e ^{x} - e ^{- x}}

Solution steps

(\frac{e ^{x} - e ^{- x}}{2})^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= \frac{1}{( \frac{e ^{x} - e ^{- x}}{2} )}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{2}{e ^{x} - e ^{- x}}

- 0.054 \cdot 3 \cdot 1 0^{- 3}

2 a e^{- (x - 3)^{2}}

e^{a t} e^{- x wt}

(5 x^{6}) (6 x^{2})

What is ((e^x-e^{-x})/2)^{-1} ?
The solution to ((e^x-e^{-x})/2)^{-1} is 2/(e^x-e^{-x)}