What is e^{-9x}(e^{6x}-3+3e^{-6x}-e^{12x}) ?

The solution to e^{-9x}(e^{6x}-3+3e^{-6x}-e^{12x}) is (3e^{-6x}-e^{12x}+e^{6x}-3)/(e^{9x)}

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simplify e^{-9x}(e^{6x}-3+3e^{-6x}-e^{12x})

simplify

e^{- 9 x} (e^{6 x} - 3 + 3 e^{- 6 x} - e^{12 x})

\frac{3 e ^{- 6 x} - e ^{12 x} + e ^{6 x} - 3}{e ^{9 x}}

Solution steps

e^{- 9 x} (e^{6 x} - 3 + 3 e^{- 6 x} - e^{12 x})

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{9 x}} (e^{6 x} + 3 e^{- 6 x} - e^{12 x} - 3)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( e ^{6 x} - 3 + 3 e ^{- 6 x} - e ^{12 x} )}{e ^{9 x}}

1 \cdot (e^{6 x} - 3 + 3 e^{- 6 x} - e^{12 x}) = e^{6 x} - 3 + 3 e^{- 6 x} - e^{12 x}

= \frac{e ^{6 x} - 3 + 3 e ^{- 6 x} - e ^{12 x}}{e ^{9 x}}

400 e^{- 2 p}

9.2 \cdot 1 0^{- 5}

(\frac{50}{2.447 \cdot 1 0 ^{- 3}}) \cdot 1 0^{- 6}

1.96 \cdot 1 0^{- 3} \cdot 2.0591

((a^{2})^{- 4})^{6}

What is e^{-9x}(e^{6x}-3+3e^{-6x}-e^{12x}) ?
The solution to e^{-9x}(e^{6x}-3+3e^{-6x}-e^{12x}) is (3e^{-6x}-e^{12x}+e^{6x}-3)/(e^{9x)}