What is sqrt(*+\sqrt{2^2+1=1)} ?

The solution to sqrt(*+\sqrt{2^2+1=1)} is \sqrt[4]{1*1=+2^2}

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simplify sqrt(*+\sqrt{2^2+1=1)}

simplify

\cdot + 2^{2} + 1 = 1

Solution steps

2^{2} + 1 = 1

Apply radical rule:

a = a^{\frac{1}{2}}

= ((2^{2} + 1 = 1)^{\frac{1}{2}})^{\frac{1}{2}}

Apply exponent rule:

(a^{b})^{c} = a^{b c},

assuming

a \geq 0

= (2^{2} + 1 = 1)^{\frac{1}{2} \cdot \frac{1}{2}}

\frac{1}{2} \cdot \frac{1}{2} = \frac{1}{4}

= (2^{2} + 1 = 1)^{\frac{1}{4}}

(3 a^{5} b) (4 a^{4} b^{7})

e^{- x} e^{3 x}

(2.4 \cdot 1 0^{- 6}) \cdot 28

40 \cdot 1 0^{- 6} (14.4)

(\frac{15}{2})^{2} \cdot \frac{1}{75} (1 - ∣ 0.3 ∣)^{2}

What is sqrt(*+\sqrt{2^2+1=1)} ?
The solution to sqrt(*+\sqrt{2^2+1=1)} is \sqrt[4]{1*1=+2^2}