What is 4piLr^2*4pir^2 ?

The solution to 4piLr^2*4pir^2 is 16pi^2Lr^4

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simplify 4piLr^2*4pir^2

simplify

4 π L r^{2} \cdot 4 π r^{2}

16 π^{2} L r^{4}

Solution steps

4 π L r^{2} \cdot 4 π r^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

4 \cdot 4 = 4^{1 + 1}

= π L r^{2} \cdot 4^{1 + 1} π r^{2}

Add the numbers:

1 + 1 = 2

= π L r^{2} \cdot 4^{2} π r^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

r^{2} r^{2} = r^{2 + 2}

= π L \cdot 4^{2} π r^{2 + 2}

Add the numbers:

2 + 2 = 4

= π L \cdot 4^{2} π r^{4}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

ππ = π^{1 + 1}

= L \cdot 4^{2} π^{1 + 1} r^{4}

Add the numbers:

1 + 1 = 2

= L \cdot 4^{2} π^{2} r^{4}

4^{2} = 16

= 16 π^{2} L r^{4}

2 π (1.3 \cdot 1 0^{- 2})

2 π \cdot 1 0^{0.5} \cdot e^{- (1 0^{0.5})^{2}}

(p^{2} q) (pq)

e^{- (\frac{4}{10})^{2}}

7.68 \cdot 1 0^{- 6}