What is (x^{(2)}+1^{(2)})^{(-2)}dx ?

The solution to (x^{(2)}+1^{(2)})^{(-2)}dx is (dx)/((x^2+1)^2)

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simplify (x^{(2)}+1^{(2)})^{(-2)}dx

simplify

(x^{(2)} + 1^{(2)})^{(- 2)} d x

\frac{d x}{( x ^{2} + 1 ) ^{2}}

Solution steps

(x^{(2)} + 1^{(2)})^{(- 2)} d x

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{( x ^{2} + 1 ^{2} ) ^{2}} d x

Apply rule

1^{a} = 1

1^{2} = 1

= \frac{1}{( x ^{2} + 1 ) ^{2}} d x

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot d x}{( x ^{2} + 1 ) ^{2}}

Multiply:

1 \cdot d x = d x

= \frac{d x}{( x ^{2} + 1 ) ^{2}}

(x^{2} + 4)^{- 1}

\frac{d}{d ^{2} x} e^{- x^{2}}

12.6 \cdot 1 0^{- 4}

- e^{- \frac{1.5}{5}}

e^{- \frac{1}{3} l n (1 - 3 y)}

What is (x^{(2)}+1^{(2)})^{(-2)}dx ?
The solution to (x^{(2)}+1^{(2)})^{(-2)}dx is (dx)/((x^2+1)^2)